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  1. #1
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    small.firearms.accuracy

    Could someone please provide a little description on the values in this file? Specifically what they affect, or alternatively is this information available somewhere I'm not finding? (I used to have a link to wiki that had some information on set files for FoW but it didn't have anything for this file).

    Code:
    (define "distance_1" 
    	{spreading 
    		{radiusTable {0 0} {10 %r1} {25 %r2} {60 %r3}}
    	}		
    )
    
    (define "accuracy_rifle"
    	("distance_1" r1(0.50) r2(1.00) r3(1.25))
    )

  2. #2
    Member Level 4 Chakal16's Avatar
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    (define "distance_1"
    {spreading
    {radiusTable {0 0} {10 %r1} {25 %r2} {60 %r3}} Meters }
    )

    (define "accuracy_rifle"
    ("distance_1" r1(0.50) r2(1.00) r3(1.25))
    ) sight radius

  3. #3
    Member Level 16 Blub0r2k's Avatar
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    not sight radius, its the radius of the spreading circle.

  4. #4
    Member Level 4 Chakal16's Avatar
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    Sorry my fail

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    Is the sight radius in meters also or does the % provide the actual percentage of the range for r# value? Let me give an example of how I think it is calculated, and please correct me if I am wrong.

    Using the OP, at a range of 60m the spreading radius should be 60X1.25%=.75m

    Thanks in Advance

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    Member Level 4 Chakal16's Avatar
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    (define "distance_1"
    {spreading
    {radiusTable {0 0} {10 %r1} {25 %r2} {60 %r3}} Meters }
    )

    (define "accuracy_rifle"
    ("distance_1" r1(0.50) r2(1.00) r3(1.25))
    )
    With that r1= 10 m, 0.50 m spread radius

  7. #7
    Member Level 16 Blub0r2k's Avatar
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    nope its on 60m = 1,25m spread circle radius

  8. #8
    Member Level 4 Chakal16's Avatar
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    yes, 10m = 0.50 25m = 1.0m and 60m=1,25m

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    Thanks guys.

    Another question, slightly off topic but related. I am trying to figure out how spreading changes with automatic weapon fire. The following is from mgun.pattern

    {Spreading 1
    {SpreadPower 1}
    {BurstAccuracy 100 98 94 90 85 80 75 70 65 60}

    and

    {burst
    {short 7 0.5}
    {long 30 5}

    Does anyone know the formulas that combine these together? I assume they are modifiers to the original spread pattern, but can't figure it out myself.

  10. #10
    Member Level 16 Blub0r2k's Avatar
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    as far as i understand the source code, it dertermines the % of the original spreading after an amout of shots fired in a row :

    1st shot : 100% of the original accuracy , 2nd shot 98% and so on.

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